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A 83.3 kg solid cylinder, 2.93 m long and with an end radius of 3.7 cm, stands on one end. How much pressure does it exert? The acceleration of gravity is 9.8 m/s2 . Answer in units of kPa.

help its for a homework assignment
Question asked by: luisito

Asked on: 06 Jan 2011

Try multiplying all the numbers together and that might be the answer.

Seriously though, the formula for this can be found in any textbook so all you have to do is read the piece of your textbook that accompanies the exercise and then learn for yourself how to do it!

By: knowitall
Replied at: 08 Jan 2011
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Comments and other answers:

Use, F: m*g m= mass of cylinder, Area of cylinder(A)= 3.142.(radius)^2.(length) Finally, Pressure(p)= F/A
By: Rabin@99

Date of comment: Mon, Mar 3rd 2014

In general to calculate fomlula is p=f/a where p=pressre f=force a=area of cylinder
By: sargunan

Date of comment: Sun, May 19th 2013

Hmm..so P=F/A,....F=W=mg=(83.3)(9.8)=816.34N..Area of cyclinder=2x22/7x(0.037x0.037)+2x22/7x0.037x2.93=0.6900 m^2...P=W/A=816.34N/0.6900m^2=1183.1Pa=1.183Kpa...ty...
By: HangNaim

Date of comment: Fri, Feb 10th 2012

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Question Keywords

exert  endhow  pressure  acceleration  gravity  units  kpa  

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