A 83.3 kg solid cylinder, 2.93 m long and with an end radius of 3.7 cm, stands on one end. How much pressure does it exert? The acceleration of gravity is 9.8 m/s2 . Answer in units of kPa.
Question asked by: luisito
Asked on: 06 Jan 2011

Try multiplying all the numbers together and that might be the answer.
Seriously though, the formula for this can be found in any textbook so all you have to do is read the piece of your textbook that accompanies the exercise and then learn for yourself how to do it!
By: knowitall
Replied at: 08 Jan 2011
Average rating for this answer is 1 / 5
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Hmm..so P=F/A,....F=W=mg=(83.3)(9.8)=816.34N..Area of cyclinder=2x22/7x(0.037x0.037)+2x22/7x0.037x2.93=0.6900 m^2...P=W/A=816.34N/0.6900m^2=1183.1Pa=1.183Kpa...ty...
By: HangNaim
Date of comment: Fri, Feb 10th 2012
Comments and other answers:
Hmm..so P=F/A,....F=W=mg=(83.3)(9.8)=816.34N..Area of cyclinder=2x22/7x(0.037x0.037)+2x22/7x0.037x2.93=0.6900 m^2...P=W/A=816.34N/0.6900m^2=1183.1Pa=1.183Kpa...ty...By: HangNaim
Date of comment: Fri, Feb 10th 2012
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Question Keywords
exert  endhow  pressure  acceleration  gravity  units  kpa  
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