A 83.3 kg solid cylinder, 2.93 m long and with an end radius of 3.7 cm, stands on one end. How much pressure does it exert? The acceleration of gravity is 9.8 m/s2 . Answer in units of kPa.
Question asked by: luisito
Asked on: 06 Jan 2011
Try multiplying all the numbers together and that might be the answer.
Seriously though, the formula for this can be found in any textbook so all you have to do is read the piece of your textbook that accompanies the exercise and then learn for yourself how to do it!
By: knowitall
Replied at: 08 Jan 2011
Average rating for this answer is 1 / 5
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Comments and other answers:
Use,
F: m*g
m= mass of cylinder,
Area of cylinder(A)=
3.142.(radius)^2.(length)
Finally,
Pressure(p)= F/A
By: Rabin@99
Date of comment: Mon, Mar 3rd 2014
By: Rabin@99
Date of comment: Mon, Mar 3rd 2014
In general to calculate fomlula is p=f/a
where
p=pressre
f=force
a=area of cylinder
By: sargunan
Date of comment: Sun, May 19th 2013
By: sargunan
Date of comment: Sun, May 19th 2013
Hmm..so P=F/A,....F=W=mg=(83.3)(9.8)=816.34N..Area of cyclinder=2x22/7x(0.037x0.037)+2x22/7x0.037x2.93=0.6900 m^2...P=W/A=816.34N/0.6900m^2=1183.1Pa=1.183Kpa...ty...
By: HangNaim
Date of comment: Fri, Feb 10th 2012
By: HangNaim
Date of comment: Fri, Feb 10th 2012
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Question Keywords
exert endhow pressure acceleration gravity units kpa
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