A drawer contains 50 bolts and 150 nuts.half of bolts and half of nuts are rusted.if one is chosen at random,what is the probability of that is rusted or bolt.
Question asked by: mathana18
Asked on: 08 Sep 2009

50 bolts and 150 nuts
25 rusted bolts, 75 rusted nuts
Therefore chance that when pick one it is a bolt is: 50/200 or 1/4
Chance that what you take out is rusted is 100/200 or 1/2
By: knowitall
Average rating for this answer is 2.5 / 5
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P(rust) = 100/200 = 1/2
p(bolt) = 50/200 = 1/4
p(rust or bolt) = p(rust) + p(bolt) - p(rust and bolt) = 1/2 + 1/4 - 25/200 = 5/8
answer is 5/8
By: don123
Date of comment: Sat, Nov 27th 2010
Comments and other answers:
P(rust) = 100/200 = 1/2
p(bolt) = 50/200 = 1/4
p(rust or bolt) = p(rust) + p(bolt) - p(rust and bolt) = 1/2 + 1/4 - 25/200 = 5/8
answer is 5/8By: don123
Date of comment: Sat, Nov 27th 2010
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Question Keywords
rusted  nuts  bolts  random  probability  bolt  contains  
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