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Kinematics

a vegetable truck leaves a stop and accelerates along a straight road at 3.0*10^-4km/s^2.determine the time taken and distance travelled by the truck to reach a speed of 1200meters per minute(4marks)
Question asked by: kiem1992

Asked on: 02 Feb 2012

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Hmm...u=0m/s,a=3.0x10^-4km/s^2=3.0x10^-4x10^3m/s^2=0.3m/s^2,v=1200m/min=1200m/60s=20m/s...so v^2=u^2+2as....(20)^2=0^2+(2x0.3)(s)..s=400/0.6=2000/3m... s=(u+v/2)t...2000/3=(0+20/2)t...10t=2000/3=200/3s..
By: HangNaim

Date of comment: Sat, Feb 11th 2012

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