...Beauty, cleaning, DIY tips and more - free to join!
   Login   Contact us   Site map   Puzzle Club   Ask a question    Newsletter


show (lim (x to 0)) sin4x / sinx cosx =4 and (lim ( x to 0)) sin2xsin3x / x^2 = 6 then ( using that and squeezing principle )show (lim (x to 0) [(3sin4x/ sinxcosx) - (2sin2xsin3x/ x^2)][sin(e^x)] = 0
Question asked by: mimikoyan

Asked on: 25 Mar 2009

Sorry this makes no sense looks like this is the sort of thing to post in a specialist maths forum! Maybe try the maths club in the clubs section here?
By: knowitall
Replied at: 05 Apr 2009
Rate Answer
Comment or provide your answer to this question
No comments have been added to this question "Limits".
Ask a New Question

Find out more about Maths

Maths Questions and Answers

functions Questions and Answers

Next question: Limit of function

Become a Member! It's Free >>>

Share on Facebook: On Twitter: TwitterTweet this!

Question Keywords


More Questions:

How Much Is A Ladies Gross Income
If The Answer Of The Sum Is 1000 And You Can Only Use 88888888 How Do You Work This Out?
If 148 Is 100% What Is 63
2 Power 56 When Divided By 17 Leaves A Remainder Of?