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Limits

show (lim (x to 0)) sin4x / sinx cosx =4 and (lim ( x to 0)) sin2xsin3x / x^2 = 6 then ( using that and squeezing principle )show (lim (x to 0) [(3sin4x/ sinxcosx) - (2sin2xsin3x/ x^2)][sin(e^x)] = 0
Question asked by: mimikoyan

Asked on: 25 Mar 2009

Sorry this makes no sense looks like this is the sort of thing to post in a specialist maths forum! Maybe try the maths club in the clubs section here?
By: knowitall
Replied at: 05 Apr 2009
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