show (lim (x to 0)) sin4x / sinx cosx =4
and (lim ( x to 0)) sin2xsin3x / x^2 = 6
then ( using that and squeezing principle )show
(lim (x to 0) [(3sin4x/ sinxcosx) - (2sin2xsin3x/ x^2)][sin(e^x)] = 0 Question asked by: mimikoyan
Asked on: 25 Mar 2009
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Sorry this makes no sense looks like this is the sort of thing to post in a specialist maths forum! Maybe try the maths club in the clubs section here?
Replied at: 05 Apr 2009Rate Answer
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