Probability question?

a red car(r)a blue car(b)and a green car(g) are randomly parked in a line on a narrow drive a)list all the possible orders in which the cars could be parked b) what is the probability that the blue car (b) first on the drive? c)what is the probability that the blue car (b) is not first on the drive?
Question asked by: cute cat

Asked on: 07 Jan 2010

Lots of probability related questions here!

There are six combinations of the cars as follows. You know this because there are three possible combinations for the first car, two possible combinations then for the second car and then only one option for the third car.

This makes 3 x 2 x 1 options which is 6. For clarity I list them for you here:

RBG
RGB
BRG
BGR
GRB
GBR

With regard to the second question, you can see that in two of the six combinations the blue car is first. So this means the probability is 2/6 or reduced down, 1/3 that the blue car is first.

Final question: if it is first in 2/6 cases then it is not first in 4/6 cases, since there are 6 in total. So there is a 2/3 chance it is not first.
By: mrquestion
Replied at: 08 Jan 2010
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