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The rate of a function....a ballis shot upwards from the roof of a classroom at a high school.its height h(t),in metres,above the ground after t seconds is given by equation...h(t)=6+80(t)-5t2 how high is the roof above the ground?


Question asked by: lovelymeme

Asked on: 07 May 2010

I am no physicist, but this strikes me as a bizarre way to try to measure the height of a building. I appreciate that it may be of interest in a purely hypothetical, intellectual sense, but as a practical way of measuring anything, it seems very complicated. How far does the ball travel upwards before it starts decelerating prior to falling back downwards? Is there a wind acting as a drag on the ball? It just seems to me that there are too many variables.

You would do much better to stand on the roof of the classroom and DROP the ball. You could then use a fairly simple equation to calculate the height of the building. As I say, I'm no physicist but broadly speaking, you would take the constant of gravitational acceleration together with the duration of the fall in seconds to work out the distance travelled by the ball, thus giving the height in feet of the building.

By: BoJofan
Replied at: 19 May 2010
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Question Keywords

ground  roof  high  seconds  rate  given  equationht680t5t2how  

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