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Time & Work

A and B, working separately, can mow a field in 12 and 15 hours respectively. They work alternately, each for one hour, with A beginneing at 5 a.m. At what time will the mowing be completed?
Question asked by: Chanakya69

Asked on: 09 Nov 2008

You are only as quick as the slowest person, therefore it will take 15 hours.
By: Unknown
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A's and B's 1 day work will be 1/12 and 1/15 respectively. In 1st 2 hrs work done = (1/12)+(1/15) = (3/20)th part of field In first 6 * 2 = 12 hours = (6 * 3)/20 =(18/20)th part Remaining work = 1-(18/20) = 1/10 In 13th hour A will mow (1/12)th part of the field so remaining work = (1/10)-(1/12) = (6-5)/60 = 1/60 B will finish mowing in [(1/60)/(1/15)] hrs = (1/60) * 15 = 1/4 hrs = 60 min Total time taken = 12 +1 +(1/4) = 13 hrs 15 min So work will finish at 5 + 13.15 = 18.15 hrs = 6.15 pm
By: Chanakya69

Date of comment: Fri, Dec 5th 2008

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