Time & Work
Question asked by: Chanakya69
Asked on: 09 Nov 2008
You are only as quick as the slowest person, therefore it will take 15 hours.
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A's and B's 1 day work will be 1/12 and 1/15 respectively.
In 1st 2 hrs work done = (1/12)+(1/15)
= (3/20)th part of field
In first 6 * 2 = 12 hours
= (6 * 3)/20
=(18/20)th part
Remaining work = 1-(18/20)
= 1/10
In 13th hour A will mow (1/12)th part of the field
so remaining work = (1/10)-(1/12)
= (6-5)/60
= 1/60
B will finish mowing in [(1/60)/(1/15)] hrs
= (1/60) * 15
= 1/4 hrs
= 60 min
Total time taken = 12 +1 +(1/4)
= 13 hrs 15 min
So work will finish at 5 + 13.15
= 18.15 hrs
= 6.15 pm
By: Chanakya69
Date of comment: Fri, Dec 5th 2008
Comments and other answers:
A's and B's 1 day work will be 1/12 and 1/15 respectively.
In 1st 2 hrs work done = (1/12)+(1/15)
= (3/20)th part of field
In first 6 * 2 = 12 hours
= (6 * 3)/20
=(18/20)th part
Remaining work = 1-(18/20)
= 1/10
In 13th hour A will mow (1/12)th part of the field
so remaining work = (1/10)-(1/12)
= (6-5)/60
= 1/60
B will finish mowing in [(1/60)/(1/15)] hrs
= (1/60) * 15
= 1/4 hrs
= 60 min
Total time taken = 12 +1 +(1/4)
= 13 hrs 15 min
So work will finish at 5 + 13.15
= 18.15 hrs
= 6.15 pmBy: Chanakya69
Date of comment: Fri, Dec 5th 2008
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