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# Find the equation of the line through the point (2,-3) which is parallel to the line with equation 5x+3y-2=0

Question asked by: knowitall

Find the equation of the line through the point (2,-3) which is parallel to the line with equation 5x+3y-2=0

5x + 3y – 2 = 0

Straight line equation:

3y = 2 – 5x

Giving slope of line 5/3

The equation with (2, -3) coordinates is parallel having same slope.

3y = 2 – 5x

y = 2/3 – 5/3x the constant being positional when x = 0 and y = 0

As both lines have same slope (parallel) find the new constant for line (2, -3):

Therefore, y = C – 5/3x is the equation of line (2, -3)

Insert values for x, and y

-3 = C – 5/3(2)

-3 = C –10/3

C = 1/3 (replace value for C in y = C – 5/3x)

Y = 1/3 – 5/3x (Multiply through by 3)

3y = 1 – 5x

The equation is 5x + 3y – 1 = 0

By: Unknown

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Question Keywords

equation  parallel  point

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