Find the equation of the line through the point (2,-3) which is parallel to the line with equation 5x+3y-2=0
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Find the equation of the line through the point (2,-3) which is parallel to the line with equation 5x+3y-2=0
5x + 3y – 2 = 0
Straight line equation:
3y = 2 – 5x
Giving slope of line 5/3
The equation with (2, -3) coordinates is parallel having same slope.
3y = 2 – 5x
y = 2/3 – 5/3x the constant being positional when x = 0 and y = 0
As both lines have same slope (parallel) find the new constant for line (2, -3):
Therefore, y = C – 5/3x is the equation of line (2, -3)
Insert values for x, and y
-3 = C – 5/3(2)
-3 = C –10/3
C = 1/3 (replace value for C in y = C – 5/3x)
Y = 1/3 – 5/3x (Multiply through by 3)
3y = 1 – 5x
The equation is 5x + 3y – 1 = 0
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