What is (4x-3)^2= (3x+1)^2+x^2

could you please help me with this. i tired very hard but cannot get a right answer!
Question asked by: neurology

Asked on: 21 Nov 2009

(4x-3)^2= (3x+1)^2+x^2

(4x-3)(4x-3) is 16x^2 -24x + 9
(3x+1)(3x+1) is 9x^2 + 6x + 1
By: knowitall
Replied at: 22 Nov 2009
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(4x-3)^2 = (3x+1)^2 + x^2 Or, 16x^2 – 24x + 9 = 9x^2 + 6x + 1 + x^2 Or, 6x^2 – 30x + 8 = 0 Or, 3x^2 – 15x + 4 = 0 Or, x = [-(-15)(+/-)√{(-15)^2 – 4*3*4}]/2*3 Hence, x = 4.717 or, x = 0.2826
By: psahu63

Date of comment: Wed, Sep 8th 2010

Hello, i need to find the value of x. that is only half bit u have explained. and i have already got to that point. at the end i come up with 6x^2-30x+8=0 i need to get the value of x. i tried the quadratic formula, a(x+p)^2+r formul, (x+p)(x+q) formula but none of them give me the correct answer whihc is x=7
By: neurology

Date of comment: Sun, Nov 22nd 2009

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