Find the value of x which gives sinx=logx
Question asked by: komalv
Asked on: 13 Jan 2010
I would also like to know the answer to this question: I remember seeing this before back when I was at school but I can't remember what the answer is now or how to work it out, other than trial and error... is there a better way thatn trial and error of working this out?
By: knowitall
Replied at: 13 Jan 2010
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The value of x for which sin x=log x can be found by plotting a graph of sin x and log x and where the two intersects will be the required value of x . required value is 2.6970(approximately)
By: ameerhamza
Date of comment: Mon, Aug 2nd 2010
Yes using Newton's method. Let f(x)=sinx-logx
Then use iterative formula x=x-(f(x))/(f'(x))
By: IsaacN
Date of comment: Mon, Jun 7th 2010
Yes there is!
Newton's mathod will work i.e xn+1=xn - f(xn)/f'(xn). Define f(x)= sinx-logx and this will converge to the root for sufficiently close initial guess
By: IsaacN
Date of comment: Mon, Jun 7th 2010
Comments and other answers:
The value of x for which sin x=log x can be found by plotting a graph of sin x and log x and where the two intersects will be the required value of x . required value is 2.6970(approximately)By: ameerhamza
Date of comment: Mon, Aug 2nd 2010
Yes using Newton's method. Let f(x)=sinx-logx
Then use iterative formula x=x-(f(x))/(f'(x))By: IsaacN
Date of comment: Mon, Jun 7th 2010
Yes there is!
Newton's mathod will work i.e xn+1=xn - f(xn)/f'(xn). Define f(x)= sinx-logx and this will converge to the root for sufficiently close initial guessBy: IsaacN
Date of comment: Mon, Jun 7th 2010
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gives sinxlogx value
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